Jika ³log2 = a dan ²log 7 = b  maka ¹⁴ log 81 = ….?

By Posted on

Jika ³log2 = a dan ²log 7 = b  maka ¹⁴ log 81 = ….?

Jawaban Terkonfirmasi

^{3}log_{2} = a \ ^{2}log_{7} = b \ ^{14}log_{81} = ...
Penyelesaian :

= frac{^{2}log_{81}}{^{2}log_{14}} \ = frac{^{2}log_{(9*9)}}{^{2}log_{7*2}} \ = frac{^{2}log_{(3^{2}*3^{2})}}{^{2}log_{7+^{2}log{2}}} \ = frac{^{2}log_{3^{2}}^{2}+^{2}log_{3^{2}}}{^{2}log_{7+^{2}log{2}}} \ = frac{2.^{2}log_{3}+2.^{2}log_{3}}{^{2}log_{7+^{2}log{2}}} \ = frac{2.(1/a)+2.(1/a)}{b+1} \ = frac{2/a+2/a}{b+1}

Setelah itu Kalikan a/a :

= frac{a}{a} *frac{2/a+2/a}{b+1}

= frac{2a/a+2a/a}{ab+a}

= frac{2+2}{ab+a}

= frac{4}{ab+a}

³log2 = a
²log7 = b

= ¹⁴log81
= ¹⁴log3₄
= 4¹⁴log3
= 4 / ³log14
= 4 / ³log2 x ³log7
= 4 / a x ab
= 4 / a(1 x b)