Kak mohon bantuannya pliss

Kak mohon bantuannya pliss

Jawab:

$displaystyle text{AC}^2=text{AB}^2+text{BC}^2\text{AC}^2=6^2+6^2\text{AC}^2=2cdot6^2\text{AC}=6sqrt2,text{cm}\\text{AG}^2=text{AC}^2+text{GC}^2\text{AG}^2=2cdot6^2+6^2\text{AG}^2=3cdot6^2\text{AG}=6sqrt3,text{cm}\\cosangle(text{AC},text{AG})=frac{text{AC}}{text{AG}}\cosangle(text{AC},text{AG})=frac{6sqrt2}{6sqrt3}\cosangle(text{AC},text{AG})=frac{1}{3}sqrt6$

$+++++++++++++++:::text{R.E.I}:::+++++++++++++++~$

$displaystyle text{QS}^2=text{PQ}^2+text{PS}^2\text{QS}^2=9^2+9^2\text{QS}^2=2cdot9^2\text{QS}=9sqrt3,text{cm}\\text{QW}^2=text{QS}^2+text{SW}^2\text{QW}^2=2cdot9^2+9^2\text{QW}^2=3cdot9^2\text{QW}=9sqrt3,text{cm}\\left[Deltatext{QWS}right]=left[Deltatext{QWS}right]\frac12text{QS}cdottext{SW}=frac12text{QW}cdot x\frac12cdot9sqrt2cdot9=frac12cdot9sqrt3cdot x\sqrt2cdot9=sqrt3cdot x\x=3sqrt6,text{cm}$

Beberapa konsep yang dipakai:

$displaystylecircrangle:text{Bangun Datar dan Bangun Ruang}\triangleright~aperp bRightarrow a^2+b^2=c^2$

$displaystyle circrangle:text{Eksponen, Bentuk Akar, dan Logaritma}\triangleright~sqrt{ab}=sqrt atimessqrt b\triangleright~frac{asqrt b}{csqrt d}=frac{asqrt {bd}}{cd}$

$displaystylecircrangle:text{Trigonometri}\triangleright~xperp yRightarrow costheta=frac{x}{sqrt{x^2+y^2}}$