Kak tolong bantu cara penyelesaianya kak terimaksih*noted jawaban sudah ditandai
Persamaan Trigonometri
3 tan (2x – π/6) = √3
tan (2x – π/6) = 1/√3
•
2x – π/6 = 30° + k.360°
2x = π/6 + π/6 + k.2π
x = π/6 + k.π … (1)
2x – π/6 = 210° + k.360°
2x = π/6 + 7π/6 + k.2π
x = 2π/3 + k.π … (2)
k bilangan bulat
k = 0 → x = π/6 , 2π/3
k = 1 → x = 7π/6 , 5π/3
dan seterusnya
Interval π ≤ x ≤ 2π
HP = {7π/6 , 5π/3}