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PEMBAHASAN

Q = m . c . ∆T

63000 J = 0,5 kg . 4200 J/kg°C . (T2 – 25°C)

63000 J = 2100(T2 – 25°C)

63000 J = 2100T2 – 52500

63000 + 52500 = 2100T2

115500 = 2100T2

115500 ÷ 2100 = T2

55°C = T2

Kesimpulan:

Jadi, suhu akhir air adalah 55°C.

Jawaban:

55°C

Penjelasan:

Dik:

Q = 63.000 J

m = 0,5 kg

T1 = 25°C

c = 4.200 J/kg°C

Dit:

T2

Jawab:

Q = m × c × ∆T

m × c × (T2 – T1) = Q

0,5 × 4.200 × (T2 – 25) = 63.000

2.100 × (T2 – 25) = 63.000

T2 – 25 = 63.000/2.100

T2 – 25 = 30

T2 = 30 + 25

T2 = 55°C

Semoga membantu ya…