Kak tolonglah dijawab ya???pake cara soalnya saya belum paham caranya
nilai mutlak
jika |a| ≤ |b|„ maka (a + b)(a – b) ≤ 0
|2x – 2| ≤ |x + 2|
(2x – 2 + x + 2)(2x – 2 – (x + 2)) ≤ 0
(3x)(x – 4) ≤ 0
3x ≥ 0 ∩ x – 4 ≤ 0
x ≥ 0 ∩ x ≤ 4
0 ≤ x ≤ 4
nilai x yang memenuhi :
0 ≤ x ≤ 4
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cara lain
|2x – 2| ≤ |x + 2|
-(x + 2) ≤ 2x – 2 ≤ x + 2
2x – 2 ≥ -(x + 2)
2x – 2 ≥ -x – 2
2x + x ≥ 2 – 2
3x ≥ 0
x ≥ 0
atau
2x – 2 ≤ x + 2
2x – x ≤ 2 + 2
x ≤ 4
nilai x yg memenuhi :
0 ≤ x ≤ 4