Kakak kakak jenius Branly Tolong Bantu tugas Sekolah Saya ini.

#jangan asal
#Disertai Penjelasan Yang Jelas
#Jangan Copas
#Point 50

Kakak kakak jenius Branly Tolong Bantu tugas Sekolah Saya ini.

Jawab:

Penjelasan dengan langkah-langkah:

soal1

$sf T_1 = matrik M_{y = -x} = left[begin{array}{ccc}sf0&sf -1\sf -1&0end{array}right] \\\T_2 = Matrtiks M_{R_{-90}} = left[begin{array}{ccc}sf0&sf 1\sf -1&0end{array}right]\\\Matriks transformasi untuk T_1 dilanjutkan T_2 = T_2oT_1\\\M = left[begin{array}{ccc}sf0&sf 1\sf -1&0end{array}right]. left[begin{array}{ccc}sf0&sf -1\sf -1&0end{array}right] = left[begin{array}{ccc}sf-1&sf0\sf 0&1end{array}right]$

soal 2

Matrik Tansformasi T1 dilanjutkan T2 = T2 o T1

Bayangan P(4, 10) = P' (x.'. y')

$sf P'= T_2oT_1 [P]\\\left[begin{array}{ccc}sf x'\sf y'end{array}right] = left[begin{array}{ccc}1&0\0&1end{array}right] left[begin{array}{ccc}0&2\2&0end{array}right] left[begin{array}{ccc}sf 4\sf10end{array}right] \\\left[begin{array}{ccc}sf x'\sf y'end{array}right] = left[begin{array}{ccc}1&0\0&1end{array}right] left[begin{array}{ccc}sf 20\sf8end{array}right] = left[begin{array}{ccc}sf 20\sf8end{array}right]$

soal 3

$sf M_1 = Matriks R_{y = x} = left[begin{array}{ccc}0&1\1&0end{array}right] \\\M_2 = left[begin{array}{ccc}1&2\0&1end{array}right] \\\ left[begin{array}{ccc}x'\y'end{array}right] = left[begin{array}{ccc}1&2\0&1end{array}right]. left[begin{array}{ccc}0&1\1&0end{array}right] left[begin{array}{ccc}x\yend{array}right]end{array}right]$

$sf left[begin{array}{ccc}x'\y'end{array}right] = left[begin{array}{ccc}2&1\1&0end{array}right] left[begin{array}{ccc}x\yend{array}right]end{array}right]\\\sf left[begin{array}{ccc}x\yend{array}right] = dfrac{1}{2(0) -1(1)}left[begin{array}{ccc}0&-1\-1&2end{array}right] left[begin{array}{ccc}x'\y'end{array}right]end{array}right]\\$

$sf left[begin{array}{ccc}x\yend{array}right] = -left[begin{array}{ccc}0&-1\-1&2end{array}right] left[begin{array}{ccc}x'\y'end{array}right]end{array}right]\\$

$sf left[begin{array}{ccc}x\yend{array}right] = left[begin{array}{ccc}0&1\1&-2end{array}right] left[begin{array}{ccc}x'\y'end{array}right]end{array}right]\\$

x = x'

y = - x' - 2y'

sub ke garis 2x + y + 4 = 0

2(x') + (- x' – 2y') + 4 = 0

2x' - x' – 2y' + 4= 0

x' - 2y' + 4= 0

bayangan x – 2y + 4 = 0

Jawaban:

jawaban no 1 – 3 tertera di foto beserta jalannya, semoga membantu:)

Gambar Jawaban