kedalam 25 g air dilarutkan 3 g urea (NH2)2CO. berapakah titik beku larutan urea tersebut jika harga Kf air = 1,86 derajat C m dan titik beku air = 0 derajat C

SIFAT KOLIGATIF LARUTAN
[Penurunan Titik Beku]

Mr = 60
wp = 25 gram
wt = 3 gram
Kf = 1,86
Tf° = 0°C
Tf = ……………?

ΔTf = wt/Mr x 1000/wp x Kf
= 3/60 x 1000/25 x 1,86
= 0,05 x 40 x 1,86
= 3,72°C

Tf = Tf° – ΔTf
= 0 – 3,72
= -3,72°C