Kelarutan Zn(OH)₂ dalam air = 5 x 10⁻⁶ mol/liter. Hasil kali kelarutannya adalah….​

Jawaban:

5×10^-16 M

Penjelasan:

Zn(OH)2 => Zn^2+ + 2 OH-

s 2s

Ksp = [Zn^2+] [OH-]^2

Ksp = s. ( 2s )^2

Ksp = 4s^3

Ksp = 4 ( 5×10^-6 )^3

Ksp = 500×10^-18 M ~ 5×10^-16 M

Jawaban:

5 x 10-¹⁶

Penjelasan:

Ksp = [Zn²+] [OH-]² = s.(2s)²

= (5 x 10-⁶) ( 10-⁵)²

= 5 x 10-⁶ x 10-¹⁰

= 5 x 10-¹⁶