Kerjain pake caranya ya ka!Jangan ngasal!​

Jawab:

Penjelasan dengan langkah-langkah:

vektor

__

soal

|a| = √3

(a-b) (a + b) =  -1

a²- b² = – 1 —> b² = a² + 1

b² = √3² + 1 =  3 + 1 = 4

b = ± 2

b (b – a) = 1

b² – ab = 1 —> ab = b² – 1

ab =  4 – 1

ab =  3

ab =  |a|. |b| . cos (a,b)

3 =  (√3)(2) . cos (a,b)

cos (a, b) =   3/ (2√3) = 1/2 √3 = cos 30 = cos π/6

<(a,b) = π/6

Jawaban:

C. π / 3

Penjelasan dengan langkah-langkah:

|a| = √3 , ( a – b ) ( a + b ) = – 1

# ( a – b ) ( a + b ) = – 1

|a|² – |b|² = – 1

|b|² = |a|² + 1

|b|² ( √3 )² + 1

|b| = 4

|b| = √4

# b ( b – a ) = 1

|b|² – |a| |b| Cos B = 1

( √4 )² – ( √3 ) ( √4 ) cos b = 1

4 – √12 cos B = 1

– √12 cos b = – 3

√12 cos b = 3

cos b = 3 / 2 √3

cos b = 1 / 2

cos b = cos 60°

b = 60°

jadikan jawaban yg terbaik Y

maaf klo slh