Dgn metode subtitusi,eliminasi dan metode gabungan subtitusi dan eliminasi. Tolong bantuannya kak
Kerjakan dgn 3 metode :
Diketahui:
Harga 5 baju dan 5 celana = Rp 170.000,00.
Harga 4 baju dan 2 celana = Rp 102.000,00.
Ditanya:
Harga baju dan celana?
Jawaban:
Harga baju = Rp 17.000,00.
Harga celana = Rp 17.000,00.
Penjelasan dengan langkah-langkah:
Misalnya:
Baju = B.
Celana = C.
Barisannya adalah:
5B + 5C = 170000.
4B + 2C = 102000.
Metode substitusi:
5B + 5C = 170000
4B + 2C = 102000
5B = 170000 – 5C
4B + 2C = 102000
B = 34000 – C
4B + 2C = 102000
4(34000 – C) + 2C = 102000
136000 – 4C + 2C = 102000
-2C = -34000
C = Rp 17.000,00.
B = 34000 – 17000
B = Rp 17.000,00.
Metode eliminasi:
5B + 5C = 170000
4B + 2C = 102000
20B + 20C = 680000
-20B – 10C = -510000
10C = 170000
C = Rp 17.000,00.
5B + 5C = 170000
4B + 2C = 102000
10B + 10C = 340000
-20B – 10C = -510000
-10B = -170000
B = Rp 17.000,00.
Metode campuran:
5B + 5C = 170000
4B + 2C = 102000
20B + 20C = 680000
-20B – 10C = -510000
10C = 170000
C = Rp 17.000,00.
5B + 5(17000) = 170000
5B + 85000 = 170000
5B = 85000
B = Rp 17.000,00.
Atau,
4B + 2(17000) = 102000
4B + 34000 = 102000
4B = 68000
B = Rp 17.000,00.
Semoga Membantu.