1. x² – 7x + 12 =0
2. 2x² + x – 6 =0
serius nanya, pakai cara!!
Kerjakan menggunakan rumus abc :
Jawab:
1. x² – 7x + 12 =0
a=1 b= – 7 c= 12
x = (-b±√(b²-4ac))/2a
= ( 7±√(49 – 48))/2
= ( 7 ± 1 )/2
x1 = (7 + 1)/2 = 4
x2 = (7 – 1)/2 = 3
2. 2x² + x – 6 =0
a = 2 b = 1 c = -6
x = (-b±√(b²-4ac))/2a
x = ( -1±√(1 + 48))/4
x = ( -1 ± 7 )/4
x1 = ( -1 + 7 )/4 = 3/2
x2 = ( -1 – 7 )/4 = -2