a. 9 + log 1,8
b. 9 – log 1,8
c. 9
d. 5 + log 1,8
e. 5 – log 1,8
KOH 5,6 gram dilarutkan ke dalam 200 ml larutan CH₃COOH 1 M dan Ka CH₃COOH = 1,8 × 10⁻⁵, maka pH larutan …
Jawaban Terkonfirmasi
5,6 gram KOH
CH3COOH 1M 200 ml
Ka CH3COOH = 1,8 × 10^-5
pH…?
mol CH3COOH = M×liter
mol CH3COOH = 1 × 200/1000
mol CH3COOH = 0,2 mol
mol KOH = gr/Mr KOH
mol KOH = 5,6 / 56
mol KOH = 0,1 mol
#persamaan reaksi
…CH3COOH + KOH =》CH3COOK + H2O
M :…….0,2……….0,1
R :……..0,1………..0,1
_______________—
S :……..0,1………..—………………0,1……….0,1
*Yang sisa CH3COOH
[H^+] = Ka × Al / B.konjugasi
[H^+] = 1,8 × 10^-5 × 0,1 / 0,1
[H^+] = 1,8 × 10^-5
pH = – log [H^+]
pH = – log 1,8 × 10^-5
pH = 5 – log 1,8