Koordinat titik balik grafik fungsi y=x2-2x-15

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = x² – 2x – 15
a = 1; b = -2; c = -15

Sumbu simetri
= -b/2a
= – (-2)/(2 . 1)
= 1

y = x² – 2x – 5
y = 1² – 2 . 1 – 5
y = -6

Koordinat titik balik = (1, -6)