Kq.7² + ³√125 =Nt : ;____________;

By Admin ReiPosted on December 3, 2022

Kq.7² + ³√125 =Nt : ;____________;

${7}^{2} + sqrt[3]{125} = 54$

$to {7}^{2} = 7 times 7$

$to49$

$to sqrt[3]{125} = 5$

$to49 + 5$

$to54$

Jawaban:

7² + ³√125

= (7×7) + (³√125)

= 49 + 5

= 54

Penjelasan dengan langkah-langkah:

semoga mebantu