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Soal :
x² + 11x + 28 = 0
gunakan rumus kuadratik/kuadrat sempurna.
KUIS [+50]
Penjelasan dengan langkah-langkah:
Persamaan Kuadrat
bentuk umum ax^2 + bx + c = 0 , a ≠ O
..
x^2 + 11x + 28 = 0 , dengan menggunakan metode kuadrat sempurna
maka,
x^2 + 11x + 28 = 0
a = 1
b = 11
c = 28
..
misalkan :
d = b/2a = 11/2(1) = 11/2
e = c – (b^2/4a) = 28 – (11^2 / 4(1)) = 28 – (121/4) = (112 – 121)/4 = -9/4
..
a(x + d)^2 + e = 0
1(x + 11/2)^2 – 9/4 = 0
(x + 11/2)^2 = 9/4
(x + 11/2) = ±√9/4
solusi akar akar
(x + 11/2) = √9/4
(x + 11/2) = 3/2
x = 3/2 – 11/2
x = -8/2 = -4
..
(x + 11/2) = -√9/4
(x + 11/2) = -3/2
x = -3/2 – 11/2
x = -14/2
x = -7
HP = { -4 dan -7 }