Kurva fungsi kuadrat Y = 2x² – 4x – 16. Memotong sumbu x dititik…

By Admin ReiPosted on December 7, 2022

Kurva fungsi kuadrat Y = 2x² – 4x – 16. Memotong sumbu x dititik…

Syarat titik potong dg sumbu x : y =0
$2 {x}^{2} - 4x - 16 = 0 (bagi : 2)\ {x}^{2} - 2x - 8 = 0 \ (x + 2)(x - 4) = 0 \ x1 = - 2 : dan : x2 = 4 \$
jadi titik potong (-2,0) dan (4,0)

$2 {x}^{2} - 4x - 16 = 0 \ frac{(2x - 8)(2x + 4)}{2} = 0 \ x= 4 \ x = - 2$
semoga membantu