Larutan 0.74 g Ca(OH)2 (Mr=74) dalam 2 L air memiliki pH

Mol Ca(OH)2 = massa/Mr = 0,74/74 = 0,01 mol
M Ca(OH)2 = n/v = 0,01/2 = 0,005M
[OH-] = Mb.X = 0,005.2 = 0,01 = 10^-2M
pH = -log[OH-] = -log 10^-2 = 2