a. HBr 0.02 M
b. HNO3 0.01 M
c. NaOH 0.002 M
d. KOH 0.01 M
e. Ca(OH)2 0.001 M
Larutan berikut yang mempunyai pH = 12 adalah…
Jawaban Terkonfirmasi
HBr 0,02 M => pH = – log [H+] = – log 0,02 = 2 – log 2
HNO3 0,01 M => pH = – log[H+] = – log 0,01 = 2
NaOH 0,002 M => pOH = – log[OH-] = – log 0,002 = 3 – log 2
pH = 14 – (3 – log 2) = 11 + log 2
KOH 0,01 M => pOH = – log[OH-] = – log 0,01 = 2
pH = 14 – 2 = 12