Larutan CH3COONa 0,1m(ka CH3CooNa=1×10^-5)sebanyak 200ml memilihi PH sebesar
Jawaban Terkonfirmasi
Materi : Asam Basa
CH3COONa mengalami hidrolisis
Gunakan rumus hidrolisis garam basa
[OH-] = (10^-14/10^-5 × 0.1)^1/2
= 10^-5 M
pH = 14 + log 10^-5
= 9
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