learn and finish - Universityku

learn and finish

${sfsumlimits^{4}_{x = 2}{(2x + 5)} }$

= (2(2) + 5) + (2(3) + 5) + (2(4) + 5)

= ((2 × 2) + 5) + ((2 × 3) + 5) + ((2 × 4) + 5)

= (4 + 5) + (6 + 5) + (8 + 5)

= 9 + 11 + 13

= ((9 + 11) + 13)

= (20 + 13)

=> 33

#Koreksi

$tt{ color{f17173}{@} color{ff968a}{R} color{ffaea5}{i} color{ffc5bf}{x} color{ffc8a2}{z} color{cce2cb}{56}}$

Jawaban:

$sfsumlimits^{4}_{x=2}(2x+5)$

$sf=(2(2)+5)+(2(3)+5)+(2(4)+5)$

$sf=(4+5)+(6+5)+(8+5)$

$sf=9+11+13$

$sf=20+13$

$sf=33$