Lim x->2 (x^4 – 4x^3 + 16)/(x^3 – 8) = . . . .

lim (x⁴ – 4x³ + 16)/(x³ – 8) = – 4/3

x → 2

Pembahasan

lim (x⁴ – 4x³ + 16)/(x³ – 8)

x → 2

lim (4x³ – 12x²) / (3x²)

x → 2

= (4(2)³ – 12(2)²) / (3(2)²)

= (32 – 48)/12

= – 16/12

= – 4/3

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Limit Fungsi Aljabar

Kode: 11.2.8

Kata Kunci: dalil l'hopital

Penjelasan dengan langkah-langkah:

lim (x⁴ – 4x³ + 16)/(x³ – 8)= – 4/3

lim (x⁴ – 4x³ + 16)/(x³ – 8)= – 4/3x › 2