Limit x mendekati 0 √sinx+1 – √sin 2x+1/x ialah​

Jawaban:

Lim x→π (cos 2x – 1) / (sin x)

cos 2x = 1 – 2 sin² x

= lim x→π (1 – 2 sin² x – 1) / (sin x)

= lim x→π (-2 sin x)

= lim x→π (-2 sin π)

= 0