Limitt x mendekati 3

Limitt x mendekati 3

ubahsoal

x²- 5x – 6 , ke x² – 5x + 6

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jawab

$sf lim_{xto 3} frac{(x-3)(x-2) sin {-3(x- 3)}} {(2x-7)(tan 2(x -3) tan 2(x-3)}\\=sf lim_{xto 3} (frac{x-2}{2x-7}) (frac{(x-3)}{tan2(x-3)}) (frac{ sin {-3(x- 3)} { tan 2(x-3)})\\=sf lim_{xto 3} (frac{x-2}{2x-7}) (frac{1}{2}) (frac{-3} { 2})\\= frac{-3}{4} ( lim_{xto 3} (frac{x-2}{2x-7})) \\= frac{-3}{4}(1 ) = - frac{3}{4}$