LOGARITMA
1.) ³log5 × ⁵log27
= ³log27
= ³log3³
= 3 × ³log3
= 3 × 1
= 3
2.) ⁵log25 + ⁵log625
= ⁵log5² + ⁵log5⁴
= (2 × ⁵log5) + (4 × ⁵log5)
= (2 × 1) + (4 × 1)
= 2 + 4
= 6
3.) ⁵log5¹² + ³log3² + ¹²log12⁵
= (12 × ⁵log5) + (2 × ³log3) + (5 × ¹²log12)
= (12 × 1) + (2 × 1) + (5 × 1)
= 12 + 2 + 5
= 14 + 5
= 19
1). ³log5 × ⁵log27
= ³log5 × ⁵3log3
= 1 × 3
= 3
2). ⁵log25 + ⁵log625
= ⁵log5² + ⁵log5⁴
= 2 + 4
= 6
3). ⁵log5¹² + ³log3² + ¹²log12⁵
= 12 + 2 + 5
= 12 + 7
= 19