Logaritma dari. log(x+6)-log(x-3)=log 2 berapa?
Jawaban Terkonfirmasi
Log (x + 6) – log (x – 3) = log 2
log [(x + 6)/(x – 3)] = log 2
(x + 6)/(x – 3) = 2
x + 6 = 2(x – 3)
x + 6 = 2x – 6
6 + 6 = 2x – x
12 = x
x = 12
Logaritma dari. log(x+6)-log(x-3)=log 2 berapa?
Log (x + 6) – log (x – 3) = log 2
log [(x + 6)/(x – 3)] = log 2
(x + 6)/(x – 3) = 2
x + 6 = 2(x – 3)
x + 6 = 2x – 6
6 + 6 = 2x – x
12 = x
x = 12