Logaritma. tolong yapake cara​

² log ( 2x² – 6x – 7 ) = ³ log ( 2x – 6x – 7 )

Syarat persamaan :

f(x) = 1

2x² – 6x – 7 = 1

2x² – 6x – 7 – 1 = 0

2x² – 6x – 8 = 0

—————————- : 2

x² – 3x – 4 = 0

( x – 4 ) ( x + 1 ) = 0

x = 4 atau x = -1