Luas segitiga tersebut beserta caranya

Teorema Phytagoras
S=√A^2+T^2
S^2=A^2+T^2

Diket A=8, T=3x, S=5x

25x^2=64+9x^2
16x^2=64
x^2=4
x=√4
x=2

A=8cm, T=3.2=6cm S=5.2=10cm
L=A.T/2
L=8.6/2=24cm^2