Luas selimut kerucut 204,1 jika jari-jari 5 cm maka tentukan volume kerucut tersebut
LS = Phirs
204.1 = 3.14 x 5 x s
s = 204.1 / 15.7
s = 13..
—
t^2 = s^2 – R^2
= 13^2 – 5^2
= 169 – 25
t =
= 12..
—-
V = 1/3phir^2t
= 1/3 x 3.14 x 5^2 x 12
= 3.14 x 25 x 4
= 3.14 x 100
= 314 cm^2