Luas selimut tabung 4.440 cm² luas alas tabung 113 cm² maka berapa volume tabung?

Luas alas = phi x r^2
113 = 22/7 r^2
r^2 =( 113 x 7)/22 = 36
r = akar 36 = 6 cm

luas selimut = (2 x phi x r x r) +(2 x phi x r x t)
4.440 = (2×3.14x6x6)+(2×3.14×6+t)
4.440 = 226.08 + 37.68 t
37.68 t = 4440 – 226.08 = 4213.92
t = 4213.92/37.68 = 112 cm

volume = phi x r x r x t
= 3.14 x 6 x 6 x 112
= 12.660,48 cm3