Matematika BAB V (FUNGSI)

Matematika BAB V (FUNGSI)

Jawab:

Penjelasan dengan langkah-langkah:

4b.

$displaystyle f(x) = dfrac{3x}{x-3}\\ f(x) = dfrac{3x-9 + 9}{x-3}\\ f(x) = dfrac{3(x-3) + 9}{x-3}\\ f(x) = 3 + dfrac{9}{x-3}\\f(x+3)=3 + dfrac{9}{x}\\fleft(3+dfrac{1}{x}right)=3 +9x\fleft(3+dfrac{9}{x}right)=x+3\fleft(3+dfrac{9}{x-3}right)=x\f^{-1}(x) = 3 + dfrac{9}{x-3} = dfrac{3x-9+9}{x-3}\$

$Huge{boxed{boxed{boldsymbol{f^{-1}(x) = f(x) = dfrac{3x}{x-3}}}}}$