Matematika Hal 81 no.7 - 10 latihan 2.1 persamaan kuadrat tolong ya di jawab kakak...

Matematika Hal 81 no.7 – 10 latihan 2.1 persamaan kuadrat tolong ya di jawab kakak…

Penjelasan dengan langkah-langkah:

$7. \ 3 {x}^{2} = 2x - 4 \ 3 {x}^{2} - 2x + 4 = 0 \ \ 8. \ {x}^{2} - 5x + 6 = 0 \ (x - 6)(x + 1) = 0 \ x - 6 = 0 : = > : x = 6 \ x + 1 = 0 : = > : x = - 1 \ hp = - 1 : dan : 6 \ \ {x}^{2} + 2x - 15 = 0 \ (x + 5)(x - 3) = 0 \ x + 5 = 0 : = > : x = - 5 \ x - 3 = 0 : = > : x = 3 \ hp = - 5 : dan : 3 \ \ {x}^{2} + 4x - 12 = 0 \ (x + 6)(x - 2) = 0 \ x + 6 = 0 : = > : x = - 6 \ x - 2 = 0 : = > : x = 2 \ hp = - 6 : dan : 2 \ \ 9. \ (x - 2)(x - 5) = 0 \ {x}^{2} - 5x - 2x + 10 = 0 \ {x}^{2} - 7x + 10 = 0 \ \ 10. \ 2( {x}^{2} + 1) = x(x +3 ) \ 2 {x}^{2} + 2 = {x}^{2} + 3x \ 2 {x}^{2} - {x}^{2} - 3x + 2 = 0 \ {x}^{2} - 3x + 2 = 0$