Minta bantuannya kak, jawaban dan penjelasannya​

Penjelasan dengan langkah-langkah:

integral tentu

no. 6

₃∫⁶ (x² + 2x – 1) dx

= 1/3 x³ + x² – x]⁶₃

= 1/3 (216 – 27) + (36 – 9) – (6 – 3)

= 63 + 27 – 3

= 87

—– batas

no. 7

₁∫⁴ 1/x³ dx

₁∫ x⁻³ dx

= -1/ 2x²]⁴₁

= (-1/ 2(4)²) – (-1/ 2(1)²)

= -1/32 + 1/2

= 30/64

= 15/32