minta bantuannya ya kak. tolong bantu kerjakan meskipun hanya bisa satu nomor, tolong dijawab. ini soal materi SMA. terimakasih

2). akar² dari x² + 6x + 8 = 0
(x + 4) (x + 2)
x = -4 atau x = -2

3)2x² + 3x + 1 = 0
a = 2
b = 3
c = 1

x1+x2 = -b/a = -3/2
x1.x2 = c/a = 1/2

nilai dari
1/x1 + 1/x2
= x1+x2 / x1.x2
= (-3/2) / (1/2)
= -3/2 x 2/1
= -3

4). 2x² + 5x + 4 = 0
a = 2
b = 5
c = 4

x1 + x2 = -b/a = -5/2
x1.x2= c/a = 4/2 = 2

nilai dari
x1² + x2²
= (x1+x2)² – 2×1.x2
= (-5/2)² – 2.2
= 25/4 – 4
= 25/4 – 16/4
= 9/4

5) 3x² + 12x + 27 = 0
a = 3, b = 12, c = 27

D = b² – 4ac
D = 12² – 4.3.27
D = 144 – 324
D = -180

6) PK yg akarnya 2 dan -3
(x -2) (x – (-3) = 0
(x – 2)(x + 3) = 0
x² + 3x – 2x – 6 = 0
x² + x – 6 = 0

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Mapel : Matematika
Kelas : 10
Materi : Persamaandan Fungsi Kuadrat
Kata kunci : –
Kode Kategorisasi : 10.2.5