Minta tolong dijelaskan caranya??
integral a xⁿ dx = a . 1/(n+1) xⁿ⁺¹ + C
∫ (2x + 1)² dx = ∫ (4x² + 4x + 1) dx
= 4 . 1/3 x³ + 4 . 1/2 x² + x + c
= 4/3 x³ + 2 x² + x + c
Minta tolong dijelaskan caranya??
integral a xⁿ dx = a . 1/(n+1) xⁿ⁺¹ + C
∫ (2x + 1)² dx = ∫ (4x² + 4x + 1) dx
= 4 . 1/3 x³ + 4 . 1/2 x² + x + c
= 4/3 x³ + 2 x² + x + c