Minta tolong dong bantuin.intergal tak tentu​

4

∫ (x-5) (x+1) dx =…?

1

4

∫ (x² – 4x – 5) dx

1

⅓x³ – 2x² – 5x + C

4

⅓x³ – 2x² – 5x |

1

[ ⅓(4)³ – 2(4)² – 5(4) ] – [ ⅓(1)³ – 2(1)² – 5(1) ]

[ ⅓(4)³ – 2(4)² – 5(4) ] – [ ⅓(1)³ – 2(1)² – 5(1) ]

[ 64/3 – 52 ] – [ ⅓ – 7 ]

[ 64/3 – 156/3 ] – [ ⅓ – 21/3 ]

[ -92/3 ] – [ -20/3 ]

-92/3 + 20/3

-72/3

-24 OPSI E

Semoga membantu :)