Mohon bantuannya + dikasih cara
akar persamaan kuadrat
a. x²-1 =0
(x-1)(x+1)=0
x1 = 1 ; x2 = -1
b.4x²+4x+1=0
4x²+2x+2x+1=0
2x(2x+1) 1(2x+1)
(2x+1)(2x+1)=0
2×1,2 =-1
x1,x2 = -1/2
c.3x²-x+6x-2=0
(x+2) (3x-1)=0
x1 = -2 ; x2 = 1/3
d.2x²-3x+2x-3=0
(x+1)(2x-3)=0
⇒x1= -1 ; x2 = 3/2
e.4x²-4+1=0
4x²-2x-2x+1=0
(2x-1)(2x-1)=0
⇒ x1,2 = 1/2
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