Mohon bantuannya gan sama caranya...

Mohon bantuannya gan sama caranya…

$int(4 {x}^{2} + 3)(2x - 1) : dx \ = int(8 {x}^{3} - 4 {x}^{2} + 6x - 3) : dx \ = frac{8}{3 + 1} {x}^{3 + 1} - frac{4}{2 + 1} {x}^{2 + 1} + frac{6}{1 + 1} {x}^{1 + 1} - frac{3}{0 + 1} {x}^{0 + 1} + c \ = 2 {x}^{4} - frac{4}{3} {x}^{3} + 3 {x}^{2} - 3x + c$