Mohon bantuannya kak yg pinter kimiaa tolong plisss
Jawaban:
PH = -log [H3O+]
2,85 = -log [H3O+]
[H3O+] = 10^(-2,85)
pOH = 14-pH = 14 – 2,85 = 11,15
pOH = -log[OH-]
11,15 = -log[OH-]
[OH-] = 10^(-11,15)
Penjelasan:
maaf kalo salah
Mohon bantuannya kak yg pinter kimiaa tolong plisss
Jawaban:
PH = -log [H3O+]
2,85 = -log [H3O+]
[H3O+] = 10^(-2,85)
pOH = 14-pH = 14 – 2,85 = 11,15
pOH = -log[OH-]
11,15 = -log[OH-]
[OH-] = 10^(-11,15)
Penjelasan:
maaf kalo salah