MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Penjelasan:
1. a) orde reaksi A (Cari konsentrasi percobaan B yang sama) = percobaan 2 dan 4
v2 k [A]x [B]y
—- = —————
v4 k [A]x [B]y
64 k [0,2]x[0,4]y (k dan [0,4]y
—— = ————— di coret)
256 k [0,4]x[0,4]y
1 1
—-^2 = —-^x
2 2
x = 2
Orde [A] = 2
orde reaksi B (Cari konsentrasi percobaan A yang sama) = Percobaan 1 dan 2
v1 k [A]x [B]y
—- = —————
v2 k [A]x [B]y
4 k [0,2]x[0,1]y
—- = —————– (k dan [0,2]x di coret)
64 k [0,2]x[0,4]y
1 1
—-^2 = —-^y
4 4
y = 2
Orde [B] = 2
b) Persamaan Laju Reakai
v = k [A]^2[B]^2
c) Harga Konstants Laju Reaksi (k)
*)Ambil salah satu percobaan (misal v1)
v = k [A]^2[B]^2
4 = k [0,2]^2[0,1]^2
4 = k [0,04] [0,01]
k = 4
—
4 x 10-4
k = 10000
d) Harga Laju Reaksi jika [A] = 0,3 dan [B] = 0,2
v = k [0,3]^2[0,2]^2
v = 10000 [9×10-2] [4×10-2]
v = 10000 [36×10-4]
v = 36 M.s-1