MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA MOHON BANTUANNYA!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​

Penjelasan:

1. a) orde reaksi A (Cari konsentrasi percobaan B yang sama) = percobaan 2 dan 4

v2 k [A]x [B]y

—- = —————

v4 k [A]x [B]y

64 k [0,2]x[0,4]y (k dan [0,4]y

—— = ————— di coret)

256 k [0,4]x[0,4]y

1 1

—-^2 = —-^x

2 2

x = 2

Orde [A] = 2

orde reaksi B (Cari konsentrasi percobaan A yang sama) = Percobaan 1 dan 2

v1 k [A]x [B]y

—- = —————

v2 k [A]x [B]y

4 k [0,2]x[0,1]y

—- = —————– (k dan [0,2]x di coret)

64 k [0,2]x[0,4]y

1 1

—-^2 = —-^y

4 4

y = 2

Orde [B] = 2

b) Persamaan Laju Reakai

v = k [A]^2[B]^2

c) Harga Konstants Laju Reaksi (k)

*)Ambil salah satu percobaan (misal v1)

v = k [A]^2[B]^2

4 = k [0,2]^2[0,1]^2

4 = k [0,04] [0,01]

k = 4

—

4 x 10-4

k = 10000

d) Harga Laju Reaksi jika [A] = 0,3 dan [B] = 0,2

v = k [0,3]^2[0,2]^2

v = 10000 [9×10-2] [4×10-2]

v = 10000 [36×10-4]

v = 36 M.s-1