Mohon bantuannya wargaku​

Vkerucut=1/3πr²t

              = 1/3(22/7)(7cm)²(√(25cm)²-(7cm)²)

              = 22/21(49cm²)(√625cm²-49cm²)

              = 22/3(7cm²)(√576cm²)

              = 154cm²/3(24cm)

              = 154cm²(8cm)

              = 1.232cm³

T = √25² – 7²
= √625 – 49
= √576
= 24 cm

Volume kerucut = 1/3 • π • r² • t
= 1/3 • 22/7 • 7 cm • 7 cm • 24 cm
= 1/3 • 22 cm • 7 cm • 24 cm
= 1.232 cm³