Mohon bantuannya wargaku​

Lp 1/2 bola = 1/2 × 4 × π × r²

Lp 1/2 bola = 2 × 22/7 × 21 × 21

Lp 1/2 bola = 2 × 22 × 3 × 21

Lp 1/2 bola = 2.772 cm²

S = √ 72² + 21²

S = √ 5.184 + 441

S = √ 5.625

S = 75 cm

Lp selimut kerucut = π × r × s

Lp selimut kerucut = 22/7 × 21 × 75

Lp selimut kerucut = 22 × 3 × 75

Lp selimut kerucut = 4.950 cm²

Luas permukaan seluruh :

Lp = 2.772 + 4.950

Lp = 7.722 cm²

S² = r² + t²

= 21² + 72²

= 441 + 5.184

= √5.625

= 75 cm

Lp1 = πrs

= 22/7 × 21 × 75

= 66 × 75

= 4.950 cm²

Lp2 = 1/2.4πr²

= 2πr²

= 2 × 22/7 × 21 × 21

= 132 × 21

= 2.772 cm²

LpT = Lp1 + Lp2

= 4.950 + 2.772

= 7.722 cm²

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Mapel : Matematika

Kelas : 7

Bab : Pythagoras

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~Solved By Noellmantap~