Mohon bantuannya yaa:)

Mohon bantuannya yaa:)

Jawab:

Hp={15,285}

#backtoschool2019

Penjelasan dengan langkah-langkah:

$sqrt{3}cos x-sin x=sqrt{2}::text{untuk}:0^{0}leq xleq 360^{0}$

Kalikan (1/2), sehingga:

$frac{1}{2}sqrt{3}cos x-frac{1}{2}sin x=frac{1}{2}sqrt{2}\(cos30^{0})cos x-(sin 30^{0})sin x=cos 45^{0}\cos(30^{0}+x)=cos 45^{0}$

Solusi 1:

$cos(30^{0}+x)=cos 45^{0}\30^{0}+x=45^{0}+k.360\x=15^{0}+k.360^{0}\k=0 to x=15$

Solusi 2 :

$cos(30^{0}+x)=cos 45^{0}\30^{0}+x=-45^{0}+k.360\x=75^{0}+k.360\k=1 to x=285^{0}$

Hp={15,285} … (C)