Mohon dibantu ya…

A.  ₁∫² 5x² – 3x + 4 dx =
= 5/3 x³ – 3/2 x² + 4x | (2….1)
=5/3(2³-1³) – 3/2(2² -1²) + 4(2 -1)
= 5/3 (7) – 3/2(3) + 4(1)
= 35/3 – 9/2 + 4
= 67/6

d) ₀∫⁴ (5y² + 3y)/y^(1/2)  dy
= ₀∫⁴ 5y^(3/2) + 3y^(1/2) dy
= 5(2/5) y^(5/2) + 3(2/3) y^(3/2) | (4…0)
= 2 y^(5/2) + 3y^(3/2) |4…0|
= 2 (4)^(2/5) + 3 (4)^(3/2) – 0
= 2(2⁵) + 3(2³)
= 64+24
= 88

C. ₀∫² (3k² – k – 1) dk = (k³ – 1/2 k² – k) ₀l²
= ( 2³ – 1/2 2² – 2) – (0)
= 8-2-2= 4