Mohon dibantu ya dengan cara integralnya

A) f '(x) = 7x + 2
f(2) = 18

f(x) = ∫ f'  dx = ∫ 7x +2 dx = 7/2 x² + 2x +c
f(2) =18
7/2(2²) + 2(2) + c = 18
14 + 4 + c = 18
c = 0
f(x) = 7/2 x² + 2x

c) f "(x) = 10x+2
f '(1) = 5
f(3)= 8

f'(x) = ∫f '(x) dx = ∫10x + 2 = 5x² + 2x + c
f '(1) = 5
5(1²) + 2(1) + c = 5
5+2 +c = 5
c= -2

f'(x) = 5x² +2x – 2

f(x) = ∫f(x) dx = ∫ 5x² + 2x -2 dx
f(x) = 5/3 x³+ x² -2x +c
f(3) = 8
5/3(27) + (9) -(6) + c = 8
45 + 3 + c = 8
c = – 40

f(x) = 5/3 x³ +x² – 2x – 40

yg b dan d silahkan dicoba