Mohon dijawab kak Jika a=⁵log1 ;b=¹⁰lpg0,01;c=⁵log0,2;d=½log8, Tentukan nilai dari a-(b+c)/d
Jawab:
-1
Penjelasan dengan langkah-langkah:
a = 5log 1
b = 10log 0,01
c = 5log 0,2
d = 1/2log 8
Maka, nilai a – (b + c)/d adalah
= 5log 1 – (10log 0,01 + 5log 0,2)/(1/2log 8)
= 0 – (10log 1/100 + 5log 1/5)/(2^(-1)log 2^3)
= 0 – (log 10^(-2) + 5log 5^(-1))/(3/(-1) x 2log 2)
= 0 – (-2 x (1) + (-1) x 1)/(-3 x 1)
= 0 – (-2 + (-1))/(-3)
= 0 – (-3)/(-3)
= 0 – 1
= -1