Mohon dijawab ya teman teman​

Jawab:

(1.) (i) PQ = 5 cm ✅

(ii.) Luas alas = 6 cm² ✅

(iii.) Luas perm. = 156 cm² ✅

(iv.) Volume = 72 cm³ ✅

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(2.) (i) PQ = 25 cm ✅

(ii.) Luas alas = 150 cm² ✅

(iii.) Luas perm. = 2460 cm² ✅

(iv.) Volume = 5400 cm³ ✅

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Penjelasan dengan langkah-langkah:

(1.) Tripel pythagoras paling dasar

{3, 4, 5} PQ = 5 cm

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(2.) dikali 5

{3×5, 4×5, 5×5} =

{15, 20, 25} PQ = 25 cm

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Lanjutan (1.)

(ii.) Luas alas = PR×QR/2 = 3×4/2 = 12/2 = 6 cm²

(iii.) Karena PQ = 5 cm, maka Luas perm. = PR×QR + (QT×(PR+QR+PQ)) = (3×4) + (12×(3+4+5))

= 12 + 12×12 = 12 + 144 = 156 cm²

(iv.) Volume = Luas alas × QT = 6 × 12 = 72 cm³

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Lanjutan (2.)

(ii.) Luas alas = PR×QR/2 = 15×20/2 = 15×10 = 150 cm²

(iii.) Karena PQ = 25 cm, maka Luas perm. = PR×QR + (QT×(PR+QR+PQ)) = (15×20) + (36×(15+20+25))

= 300 + 36×60 = 300 + 2160 = 2460 cm²

(iv.) Volume = Luas alas × QT = 150 × 36 = 5400 cm³

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<(7o7)>