N1+n2+n3=36
n1*n2*n3=1440
Berapakah nilai dari n1, n2, dan n3 ?
Jawaban Terkonfirmasi
N₁ + n₂ + n₃ = 36
(n₁)(n₂)(n₃) = 1440
n-b + n + n+b = 36
3n = 36
n = 36/3
n = 12
(n-b)(n)(n+b) = 1440
n(n²-b²) = 1440
12(12² – b²) =1440
1728 – 12b² = 1440
– 12b² = 1440 – 1728
b² = -288/-12
b = √24 = 2√6
n₁ = 12 – 2√6
n₂ = 12
n₃ = 12 + 2√6
N1 + n2 + n3 = 36
6n = 36
n = 36
6
n = 6
n1 = (6)1 = 6
n2 = (6)2 = 12
n3 = (6)3 = 18