Nilai a adalah……..​

Integral

∫dx /x² [2a -1] = 1/2

∫x^-2 dx [2a -1]

= 1/(-2 + 1) x^(-2 + 1)

= -x^-1

= -1/x

Substitusi batas integral

-1/(2a) – (-1/(-1)) = 1/2

-1/(2a) – 1 = 1/2

-1/(2a) = 1/2 + 1

-1/(2a) = 3/2

-1/a = 3

a = -1/3