Nilai dari 3log2×2log3-2log1/6=
Jawaban Terkonfirmasi
LogAritMa
³log 2 . ²log 3 – ²log 1/16
= ³log 3 – ²log 2^-4
= 1 – (-4)
= 1 + 4
= 5
Nilai dari 3log2×2log3-2log1/6=
LogAritMa
³log 2 . ²log 3 – ²log 1/16
= ³log 3 – ²log 2^-4
= 1 – (-4)
= 1 + 4
= 5