Nilai dari 5 Σ k = 2 (2k – 1) = ..​

Penjelasan dengan langkah-langkah:

no. 1

⁵Σk=2 (2 k – 1)

= 2(2 + 3 + 4 + 5) – 1(4)

= 2(14) – 4

= 28 – 4

= 24

no. 2

¹⁰Σk=-2 (-1)^i

= (-1)⁻² + (-1)⁻¹ + (-1)⁰ + (-1)¹ + (-1)² + (-1)³ + (-1)⁴ + (-1)⁵ + (-1)⁶ + (-1)⁷ + (-1)⁸ + (-1)⁹ + (-1)¹⁰

= 1 – 1 + 1 – 1 + 1 – 1 + 1 – 1 + 1 – 1 + 1 – 1 + 1

= 1

no. 3

⁴Σi=0 (3i + i²) + ³Σj=1 (4j)

= 3(0 + 1 + 2 + 3 + 4) + (0 + 1 + 2 + 3 + 4)² + 4(1 + 2 + 3)

= 3(10) + 10² + 4(6)

= 30 + 100 + 24

= 154

Semoga Bermanfaat